{"id":570914,"date":"2026-07-27T14:50:23","date_gmt":"2026-07-27T07:50:23","guid":{"rendered":"https:\/\/hoanghamobile.com\/tin-tuc\/?p=570914"},"modified":"2026-07-27T15:08:14","modified_gmt":"2026-07-27T08:08:14","slug":"gia-toc-trong-truong-la-gi","status":"publish","type":"post","link":"https:\/\/hoanghamobile.com\/tin-tuc\/gia-toc-trong-truong-la-gi\/","title":{"rendered":"Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 g\u00ec? Gi\u00e1 tr\u1ecb g v\u00e0 c\u00e1c c\u00f4ng th\u1ee9c li\u00ean quan"},"content":{"rendered":"

Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 gia t\u1ed1c m\u00e0 m\u1ed9t v\u1eadt thu \u0111\u01b0\u1ee3c khi ch\u1ec9 ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a tr\u1ecdng l\u1ef1c, k\u00fd hi\u1ec7u l\u00e0 g; \u1edf g\u1ea7n m\u1eb7t \u0111\u1ea5t, g c\u00f3 gi\u00e1 tr\u1ecb x\u1ea5p x\u1ec9 9,8 m\/s\u00b2 (th\u01b0\u1eddng l\u00e0m tr\u00f2n 10 m\/s\u00b2 khi t\u00ednh to\u00e1n).<\/strong> \u0110\u00e2y l\u00e0 m\u1ed9t \u0111\u1ea1i l\u01b0\u1ee3ng n\u1ec1n t\u1ea3ng c\u1ee7a V\u1eadt l\u00fd, g\u1eafn li\u1ec1n v\u1edbi tr\u1ecdng l\u1ef1c, l\u1ef1c h\u1ea5p d\u1eabn<\/a>, chuy\u1ec3n \u0111\u1ed9ng r\u01a1i t\u1ef1 do v\u00e0 dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc. N\u1eafm v\u1eefng kh\u00e1i ni\u1ec7m n\u00e0y gi\u00fap b\u1ea1n hi\u1ec3u v\u00ec sao m\u1ecdi v\u1eadt \u0111\u1ec1u r\u01a1i xu\u1ed1ng \u0111\u1ea5t, t\u00ednh \u0111\u01b0\u1ee3c tr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a v\u1eadt v\u00e0 gi\u1ea3i nhanh c\u00e1c d\u1ea1ng b\u00e0i t\u1eadp c\u01a1 h\u1ecdc ph\u1ed5 th\u00f4ng. N\u1ed9i dung d\u01b0\u1edbi \u0111\u00e2y s\u1ebd \u0111i t\u1eeb \u0111\u1ecbnh ngh\u0129a, gi\u00e1 tr\u1ecb, c\u00f4ng th\u1ee9c g = GM\/R\u00b2, c\u00e1c y\u1ebfu t\u1ed1 \u1ea3nh h\u01b0\u1edfng cho \u0111\u1ebfn b\u00e0i t\u1eadp c\u00f3 l\u1eddi gi\u1ea3i chi ti\u1ebft.<\/p>\n

Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 g\u00ec?<\/h2>\n

Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 gia t\u1ed1c c\u1ee7a m\u1ed9t v\u1eadt khi r\u01a1i t\u1ef1 do, t\u1ee9c l\u00e0 khi v\u1eadt ch\u1ec9 ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a tr\u1ecdng l\u1ef1c v\u00e0 b\u1ecf qua l\u1ef1c c\u1ea3n c\u1ee7a kh\u00f4ng kh\u00ed. \u0110i\u1ec3m \u0111\u1eb7c bi\u1ec7t quan tr\u1ecdng: gia t\u1ed1c n\u00e0y kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a v\u1eadt<\/strong>. M\u1ed9t vi\u00ean bi v\u00e0 m\u1ed9t h\u00f2n \u0111\u00e1 \u0111\u01b0\u1ee3c th\u1ea3 c\u00f9ng l\u00fac t\u1eeb c\u00f9ng m\u1ed9t \u0111\u1ed9 cao (b\u1ecf qua s\u1ee9c c\u1ea3n) s\u1ebd r\u01a1i nhanh nh\u01b0 nhau v\u00e0 ch\u1ea1m \u0111\u1ea5t c\u00f9ng th\u1eddi \u0111i\u1ec3m. K\u00fd hi\u1ec7u chu\u1ea9n c\u1ee7a gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 g, \u0111\u01a1n v\u1ecb l\u00e0 m\u00e9t tr\u00ean gi\u00e2y b\u00ecnh ph\u01b0\u01a1ng (m\/s\u00b2).<\/p>\n

\"gia-toc-trong-truong-1\"<\/p>\n

Gi\u00e1 tr\u1ecb c\u1ee7a gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng<\/h2>\n

\u1ede g\u1ea7n b\u1ec1 m\u1eb7t Tr\u00e1i \u0110\u1ea5t, gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng c\u00f3 gi\u00e1 tr\u1ecb trung b\u00ecnh kho\u1ea3ng g \u2248 9,8 m\/s\u00b2<\/strong> (ch\u00ednh x\u00e1c h\u01a1n l\u00e0 9,81 m\/s\u00b2). Trong nhi\u1ec1u b\u00e0i to\u00e1n, \u0111\u1ec3 t\u00ednh nhanh ng\u01b0\u1eddi ta th\u01b0\u1eddng l\u00e0m tr\u00f2n g \u2248 10 m\/s\u00b2. Gi\u00e1 tr\u1ecb n\u00e0y c\u00f3 ngh\u0129a l\u00e0: sau m\u1ed7i gi\u00e2y r\u01a1i t\u1ef1 do, v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt t\u0103ng th\u00eam kho\u1ea3ng 9,8 m\/s. V\u00ec gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng li\u00ean h\u1ec7 tr\u1ef1c ti\u1ebfp v\u1edbi tr\u1ecdng l\u1ef1c<\/a> t\u00e1c d\u1ee5ng l\u00ean v\u1eadt, n\u00ean g c\u00e0ng l\u1edbn th\u00ec v\u1eadt c\u00e0ng “n\u1eb7ng” h\u01a1n t\u1ea1i c\u00f9ng m\u1ed9t kh\u1ed1i l\u01b0\u1ee3ng.<\/p>\n

\"gia-toc-trong-truong-2\"<\/p>\n

C\u00f4ng th\u1ee9c gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = GM\/R\u00b2<\/h2>\n

Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng t\u1ea1i m\u1ed9t \u0111i\u1ec3m \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh t\u1eeb \u0111\u1ecbnh lu\u1eadt v\u1ea1n v\u1eadt h\u1ea5p d\u1eabn c\u1ee7a Newton, theo c\u00f4ng th\u1ee9c g = GM\/R\u00b2<\/strong>. C\u00f4ng th\u1ee9c n\u00e0y cho th\u1ea5y g ph\u1ee5 thu\u1ed9c v\u00e0o kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a thi\u00ean th\u1ec3 v\u00e0 kho\u1ea3ng c\u00e1ch t\u1eeb \u0111i\u1ec3m x\u00e9t \u0111\u1ebfn t\u00e2m thi\u00ean th\u1ec3, ch\u1ee9 kh\u00f4ng ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt r\u01a1i. B\u1ea3ng d\u01b0\u1edbi \u0111\u00e2y gi\u1ea3i th\u00edch \u00fd ngh\u0129a t\u1eebng \u0111\u1ea1i l\u01b0\u1ee3ng v\u00e0 \u0111\u01a1n v\u1ecb:<\/p>\n\n\n\n\n\n\n\n\n
K\u00fd hi\u1ec7u<\/th>\n\u00dd ngh\u0129a<\/th>\n\u0110\u01a1n v\u1ecb<\/th>\n<\/tr>\n<\/thead>\n
g<\/td>\nGia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng<\/td>\nm\/s\u00b2<\/td>\n<\/tr>\n
G<\/td>\nH\u1eb1ng s\u1ed1 h\u1ea5p d\u1eabn \u2248 6,67 \u00d7 10\u207b\u00b9\u00b9<\/td>\nN\u00b7m\u00b2\/kg\u00b2<\/td>\n<\/tr>\n
M<\/td>\nKh\u1ed1i l\u01b0\u1ee3ng thi\u00ean th\u1ec3 (Tr\u00e1i \u0110\u1ea5t \u2248 5,97 \u00d7 10\u00b2\u2074)<\/td>\nkg<\/td>\n<\/tr>\n
R<\/td>\nB\u00e1n k\u00ednh thi\u00ean th\u1ec3 \/ kho\u1ea3ng c\u00e1ch t\u1edbi t\u00e2m (Tr\u00e1i \u0110\u1ea5t \u2248 6,37 \u00d7 10\u2076)<\/td>\nm<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

T\u1eeb gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng, ta suy ra c\u00f4ng th\u1ee9c t\u00ednh tr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t v\u1eadt kh\u1ed1i l\u01b0\u1ee3ng m l\u00e0 P = m \u00b7 g<\/strong>. \u0110\u00e2y l\u00e0 c\u00f4ng th\u1ee9c b\u1ea1n d\u00f9ng th\u01b0\u1eddng xuy\u00ean nh\u1ea5t khi l\u00e0m b\u00e0i t\u1eadp c\u01a1 h\u1ecdc \u1edf ph\u1ed5 th\u00f4ng. T\u1eeb tr\u1ecdng l\u01b0\u1ee3ng P, b\u1ea1n c\u0169ng c\u00f3 th\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang<\/a> c\u1ee7a v\u1eadt theo c\u00f4ng th\u1ee9c d = P\/V.<\/p>\n

Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng thay \u0111\u1ed5i theo \u0111\u1ed9 cao v\u00e0 v\u0129 \u0111\u1ed9<\/h2>\n

V\u00ec g = GM\/R\u00b2 n\u00ean gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng kh\u00f4ng c\u1ed1 \u0111\u1ecbnh m\u00e0 thay \u0111\u1ed5i theo v\u1ecb tr\u00ed. C\u00e0ng l\u00ean cao, kho\u1ea3ng c\u00e1ch R \u0111\u1ebfn t\u00e2m Tr\u00e1i \u0110\u1ea5t c\u00e0ng l\u1edbn n\u00ean g c\u00e0ng gi\u1ea3m. Ngo\u00e0i ra, do Tr\u00e1i \u0110\u1ea5t h\u01a1i d\u1eb9t \u1edf hai c\u1ef1c v\u00e0 ph\u00ecnh ra \u1edf x\u00edch \u0111\u1ea1o, c\u1ed9ng th\u00eam \u1ea3nh h\u01b0\u1edfng c\u1ee7a l\u1ef1c qu\u00e1n t\u00ednh ly t\u00e2m khi Tr\u00e1i \u0110\u1ea5t quay, n\u00ean g \u1edf v\u00f9ng c\u1ef1c l\u1edbn h\u01a1n \u1edf x\u00edch \u0111\u1ea1o. B\u1ea3ng d\u01b0\u1edbi li\u1ec7t k\u00ea gi\u00e1 tr\u1ecb g tham kh\u1ea3o t\u1ea1i m\u1ed9t s\u1ed1 n\u01a1i:<\/p>\n\n\n\n\n\n\n\n\n\n
V\u1ecb tr\u00ed<\/th>\nGi\u00e1 tr\u1ecb g (m\/s\u00b2)<\/th>\n<\/tr>\n<\/thead>\n
X\u00edch \u0111\u1ea1o (m\u1ef1c n\u01b0\u1edbc bi\u1ec3n)<\/td>\n\u2248 9,78<\/td>\n<\/tr>\n
V\u0129 \u0111\u1ed9 45\u00b0<\/td>\n\u2248 9,81<\/td>\n<\/tr>\n
Hai c\u1ef1c (B\u1eafc\/Nam)<\/td>\n\u2248 9,83<\/td>\n<\/tr>\n
\u0110\u1ec9nh Everest (~8.850 m)<\/td>\n\u2248 9,76<\/td>\n<\/tr>\n
Tr\u00ean M\u1eb7t Tr\u0103ng<\/td>\n\u2248 1,62<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00f3 th\u1ec3 th\u1ea5y tr\u00ean M\u1eb7t Tr\u0103ng g ch\u1ec9 b\u1eb1ng kho\u1ea3ng 1\/6 so v\u1edbi Tr\u00e1i \u0110\u1ea5t, \u0111\u00f3 l\u00e0 l\u00fd do c\u00e1c phi h\u00e0nh gia c\u00f3 th\u1ec3 nh\u1ea3y cao v\u00e0 b\u01b0\u1edbc \u0111i “nh\u1eb9 b\u1eabng” tr\u00ean b\u1ec1 m\u1eb7t M\u1eb7t Tr\u0103ng.<\/p>\n

\"gia-toc-trong-truong-3\"<\/p>\n

C\u00e1c c\u00f4ng th\u1ee9c li\u00ean quan \u0111\u1ebfn g<\/h2>\n

Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng xu\u1ea5t hi\u1ec7n trong nhi\u1ec1u c\u00f4ng th\u1ee9c quan tr\u1ecdng c\u1ee7a c\u01a1 h\u1ecdc v\u00e0 dao \u0111\u1ed9ng. B\u1ea3ng d\u01b0\u1edbi t\u1ed5ng h\u1ee3p nh\u1eefng c\u00f4ng th\u1ee9c b\u1ea1n c\u1ea7n ghi nh\u1edb:<\/p>\n\n\n\n\n\n\n\n\n
C\u00f4ng th\u1ee9c<\/th>\n\u00dd ngh\u0129a<\/th>\n<\/tr>\n<\/thead>\n
P = m \u00b7 g<\/td>\nTr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a v\u1eadt kh\u1ed1i l\u01b0\u1ee3ng m<\/td>\n<\/tr>\n
v = g \u00b7 t<\/td>\nV\u1eadn t\u1ed1c r\u01a1i t\u1ef1 do sau th\u1eddi gian t (t\u1eeb tr\u1ea1ng th\u00e1i ngh\u1ec9)<\/td>\n<\/tr>\n
h = \u00bd \u00b7 g \u00b7 t\u00b2<\/td>\nQu\u00e3ng \u0111\u01b0\u1eddng r\u01a1i t\u1ef1 do sau th\u1eddi gian t<\/td>\n<\/tr>\n
T = 2\u03c0\u221a(l\/g)<\/td>\nChu k\u1ef3 con l\u1eafc \u0111\u01a1n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00f4ng th\u1ee9c chu k\u1ef3 con l\u1eafc \u0111\u01a1n<\/a> c\u0169ng l\u00e0 c\u01a1 s\u1edf c\u1ee7a th\u00ed nghi\u1ec7m \u0111o g ph\u1ed5 bi\u1ebfn trong nh\u00e0 tr\u01b0\u1eddng. N\u1ebfu b\u1ea1n \u0111ang \u00f4n ph\u1ea7n dao \u0111\u1ed9ng, c\u00f3 th\u1ec3 tham kh\u1ea3o th\u00eam v\u1ec1 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/a> v\u00e0 t\u1ea7n s\u1ed1 g\u00f3c<\/a> \u0111\u1ec3 hi\u1ec3u tr\u1ecdn v\u1eb9n m\u1ed1i li\u00ean h\u1ec7 gi\u1eefa g, chu k\u1ef3 v\u00e0 t\u1ea7n s\u1ed1.<\/p>\n

C\u00e1ch x\u00e1c \u0111\u1ecbnh g b\u1eb1ng th\u00ed nghi\u1ec7m<\/h2>\n

M\u1ed9t c\u00e1ch ph\u1ed5 bi\u1ebfn \u0111\u1ec3 \u0111o gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 d\u00f9ng con l\u1eafc \u0111\u01a1n: \u0111o chi\u1ec1u d\u00e0i d\u00e2y l v\u00e0 chu k\u1ef3 dao \u0111\u1ed9ng T, r\u1ed3i \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c suy ra g = 4\u03c0\u00b2\u00b7l \/ T\u00b2<\/strong>. Ngo\u00e0i ra, c\u00f3 th\u1ec3 \u0111o b\u1eb1ng th\u00ed nghi\u1ec7m r\u01a1i t\u1ef1 do: \u0111o qu\u00e3ng \u0111\u01b0\u1eddng h v\u00e0 th\u1eddi gian r\u01a1i t, r\u1ed3i t\u00ednh g = 2h\/t\u00b2. C\u1ea3 hai ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ec1u cho k\u1ebft qu\u1ea3 x\u1ea5p x\u1ec9 9,8 m\/s\u00b2 n\u1ebfu \u0111o c\u1ea9n th\u1eadn.<\/p>\n

B\u00e0i t\u1eadp v\u1eadn d\u1ee5ng c\u00f3 l\u1eddi gi\u1ea3i<\/h2>\n
    \n
  • B\u00e0i 1:<\/strong> M\u1ed9t v\u1eadt c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 3 kg. T\u00ednh tr\u1ecdng l\u01b0\u1ee3ng (l\u1ea5y g = 9,8 m\/s\u00b2). L\u1eddi gi\u1ea3i:<\/em> \u00c1p d\u1ee5ng P = m\u00b7g = 3 \u00d7 9,8 = 29,4 N.<\/li>\n
  • B\u00e0i 2:<\/strong> V\u1eadt r\u01a1i t\u1ef1 do trong 2 gi\u00e2y, l\u1ea5y g = 10 m\/s\u00b2. T\u00ednh v\u1eadn t\u1ed1c khi ch\u1ea1m \u0111\u1ea5t. L\u1eddi gi\u1ea3i:<\/em> v = g\u00b7t = 10 \u00d7 2 = 20 m\/s.<\/li>\n
  • B\u00e0i 3:<\/strong> V\u1eadt r\u01a1i t\u1ef1 do trong 3 gi\u00e2y (g = 10 m\/s\u00b2). T\u00ednh qu\u00e3ng \u0111\u01b0\u1eddng r\u01a1i. L\u1eddi gi\u1ea3i:<\/em> h = \u00bd\u00b7g\u00b7t\u00b2 = \u00bd \u00d7 10 \u00d7 3\u00b2 = \u00bd \u00d7 10 \u00d7 9 = 45 m.<\/li>\n
  • B\u00e0i 4:<\/strong> Con l\u1eafc \u0111\u01a1n d\u00e0i 1 m c\u00f3 chu k\u1ef3 2 s. T\u00ednh g. L\u1eddi gi\u1ea3i:<\/em> g = 4\u03c0\u00b2l\/T\u00b2 = 4 \u00d7 9,87 \u00d7 1 \/ 2\u00b2 = 39,48 \/ 4 \u2248 9,87 m\/s\u00b2.<\/li>\n
  • B\u00e0i 5 (tr\u1eafc nghi\u1ec7m):<\/strong> Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng ph\u1ee5 thu\u1ed9c v\u00e0o y\u1ebfu t\u1ed1 n\u00e0o? A. Kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt r\u01a1i. B. \u0110\u1ed9 cao v\u00e0 v\u0129 \u0111\u1ed9. C. M\u00e0u s\u1eafc v\u1eadt. D. H\u00ecnh d\u1ea1ng v\u1eadt. \u0110\u00e1p \u00e1n:<\/em> B.<\/li>\n<\/ul>\n

    \"gia-toc-trong-truong-4\"<\/p>\n

    C\u00e2u h\u1ecfi th\u01b0\u1eddng g\u1eb7p v\u1ec1 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng<\/h2>\n

    Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 g\u00ec?<\/h3>\n

    Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 gia t\u1ed1c c\u1ee7a v\u1eadt khi ch\u1ec9 ch\u1ecbu t\u00e1c d\u1ee5ng c\u1ee7a tr\u1ecdng l\u1ef1c (r\u01a1i t\u1ef1 do), k\u00fd hi\u1ec7u l\u00e0 g.<\/p>\n

    Gi\u00e1 tr\u1ecb c\u1ee7a g \u1edf g\u1ea7n m\u1eb7t \u0111\u1ea5t l\u00e0 bao nhi\u00eau?<\/h3>\n

    Kho\u1ea3ng 9,8 m\/s\u00b2 (ch\u00ednh x\u00e1c 9,81 m\/s\u00b2), th\u01b0\u1eddng \u0111\u01b0\u1ee3c l\u00e0m tr\u00f2n th\u00e0nh 10 m\/s\u00b2 khi t\u00ednh to\u00e1n nhanh.<\/p>\n

    Gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng c\u00f3 ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt kh\u00f4ng?<\/h3>\n

    Kh\u00f4ng. M\u1ecdi v\u1eadt r\u01a1i t\u1ef1 do \u0111\u1ec1u c\u00f3 c\u00f9ng gia t\u1ed1c g n\u1ebfu b\u1ecf qua s\u1ee9c c\u1ea3n c\u1ee7a kh\u00f4ng kh\u00ed.<\/p>\n

    C\u00f4ng th\u1ee9c t\u00ednh gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng l\u00e0 g\u00ec?<\/h3>\n

    g = GM\/R\u00b2, trong \u0111\u00f3 G l\u00e0 h\u1eb1ng s\u1ed1 h\u1ea5p d\u1eabn, M l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng thi\u00ean th\u1ec3, R l\u00e0 kho\u1ea3ng c\u00e1ch \u0111\u1ebfn t\u00e2m thi\u00ean th\u1ec3.<\/p>\n

    V\u00ec sao g thay \u0111\u1ed5i theo v\u1ecb tr\u00ed?<\/h3>\n

    V\u00ec g ph\u1ee5 thu\u1ed9c \u0111\u1ed9 cao v\u00e0 v\u0129 \u0111\u1ed9: c\u00e0ng l\u00ean cao g c\u00e0ng gi\u1ea3m, v\u00e0 g \u1edf hai c\u1ef1c l\u1edbn h\u01a1n \u1edf x\u00edch \u0111\u1ea1o.<\/p>\n

    C\u00e1ch \u0111o g b\u1eb1ng con l\u1eafc \u0111\u01a1n nh\u01b0 th\u1ebf n\u00e0o?<\/h3>\n

    \u0110o chi\u1ec1u d\u00e0i d\u00e2y l v\u00e0 chu k\u1ef3 dao \u0111\u1ed9ng T, r\u1ed3i t\u00ednh g = 4\u03c0\u00b2l\/T\u00b2.<\/p>\n

    K\u1ebft lu\u1eadn<\/h2>\n

    T\u00f3m l\u1ea1i, gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g \u2248 9,8 m\/s\u00b2 \u1edf g\u1ea7n m\u1eb7t \u0111\u1ea5t, kh\u00f4ng ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt v\u00e0 \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c g = GM\/R\u00b2<\/strong>. \u0110\u1ea1i l\u01b0\u1ee3ng n\u00e0y xu\u1ea5t hi\u1ec7n trong h\u00e0ng lo\u1ea1t c\u00f4ng th\u1ee9c quen thu\u1ed9c nh\u01b0 P = mg, h = \u00bdgt\u00b2 v\u00e0 T = 2\u03c0\u221a(l\/g). Hi\u1ec3u r\u00f5 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng s\u1ebd gi\u00fap b\u1ea1n gi\u1ea3i nhanh c\u00e1c b\u00e0i to\u00e1n r\u01a1i t\u1ef1 do, con l\u1eafc v\u00e0 dao \u0111\u1ed9ng. B\u1ea1n c\u00f3 th\u1ec3 xem th\u00eam c\u00e1c b\u00e0i ki\u1ebfn th\u1ee9c V\u1eadt l\u00fd kh\u00e1c tr\u00ean chuy\u00ean m\u1ee5c tin t\u1ee9c c\u1ee7a Ho\u00e0ng H\u00e0 Mobile.
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