{"id":569095,"date":"2026-07-27T09:30:32","date_gmt":"2026-07-27T02:30:32","guid":{"rendered":"https:\/\/hoanghamobile.com\/tin-tuc\/?p=569095"},"modified":"2026-07-27T15:08:39","modified_gmt":"2026-07-27T08:08:39","slug":"dao-dong-dieu-hoa-la-gi","status":"publish","type":"post","link":"https:\/\/hoanghamobile.com\/tin-tuc\/dao-dong-dieu-hoa-la-gi\/","title":{"rendered":"Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 g\u00ec? Ph\u01b0\u01a1ng tr\u00ecnh, chu k\u1ef3 v\u00e0 b\u00e0i t\u1eadp"},"content":{"rendered":"

Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 dao \u0111\u1ed9ng trong \u0111\u00f3 li \u0111\u1ed9 c\u1ee7a v\u1eadt bi\u1ebfn thi\u00ean theo th\u1eddi gian theo quy lu\u1eadt h\u00e0m cosin (ho\u1eb7c sin); ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 d\u1ea1ng x = A\u00b7cos(\u03c9t + \u03c6). \u0110\u00e2y l\u00e0 d\u1ea1ng dao \u0111\u1ed9ng c\u01a1 b\u1ea3n, xu\u1ea5t hi\u1ec7n trong ch\u01b0\u01a1ng tr\u00ecnh V\u1eadt l\u00fd l\u1edbp 11 v\u00e0 12, \u0111\u1ed3ng th\u1eddi l\u00e0 n\u1ec1n t\u1ea3ng \u0111\u1ec3 hi\u1ec3u s\u00f3ng c\u01a1, s\u00f3ng \u00e2m v\u00e0 d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u. B\u00e0i vi\u1ebft n\u00e0y tr\u00ecnh b\u00e0y dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 g\u00ec<\/b>, ph\u01b0\u01a1ng tr\u00ecnh, c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng, v\u1eadn t\u1ed1c \u2013 gia t\u1ed1c, n\u0103ng l\u01b0\u1ee3ng, con l\u1eafc v\u00e0 nhi\u1ec1u b\u00e0i t\u1eadp c\u00f3 l\u1eddi gi\u1ea3i t\u1eebng b\u01b0\u1edbc \u0111\u1ec3 b\u1ea1n d\u1ec5 \u00f4n t\u1eadp.<\/p>\n

Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 g\u00ec?<\/b><\/h2>\n

Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 dao \u0111\u1ed9ng trong \u0111\u00f3 li \u0111\u1ed9 (v\u1ecb tr\u00ed) c\u1ee7a v\u1eadt so v\u1edbi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng l\u00e0 m\u1ed9t h\u00e0m cosin (ho\u1eb7c sin) c\u1ee7a th\u1eddi gian. V\u1eadt l\u1eb7p l\u1ea1i chuy\u1ec3n \u0111\u1ed9ng quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng theo chu k\u1ef3, v\u1edbi bi\u00ean \u0111\u1ed9 kh\u00f4ng \u0111\u1ed5i khi b\u1ecf qua ma s\u00e1t. Nhi\u1ec1u dao \u0111\u1ed9ng trong t\u1ef1 nhi\u00ean v\u00e0 k\u1ef9 thu\u1eadt nh\u01b0 con l\u1eafc l\u00f2 xo, con l\u1eafc \u0111\u01a1n<\/a> v\u1edbi bi\u00ean \u0111\u1ed9 nh\u1ecf, m\u00e0ng loa hay d\u00e2y \u0111\u00e0n \u0111\u1ec1u l\u00e0 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a ho\u1eb7c g\u1ea7n \u0111\u00fang l\u00e0 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f2n \u0111\u01b0\u1ee3c xem l\u00e0 h\u00ecnh chi\u1ebfu c\u1ee7a m\u1ed9t chuy\u1ec3n \u0111\u1ed9ng tr\u00f2n \u0111\u1ec1u l\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng n\u1eb1m trong m\u1eb7t ph\u1eb3ng qu\u1ef9 \u0111\u1ea1o.<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/b><\/h2>\n

Ph\u01b0\u01a1ng tr\u00ecnh li \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a: x = A\u00b7cos(\u03c9t + \u03c6). Trong \u0111\u00f3:<\/p>\n

    \n
  • x l\u00e0 li \u0111\u1ed9 (v\u1ecb tr\u00ed) c\u1ee7a v\u1eadt t\u1ea1i th\u1eddi \u0111i\u1ec3m t, \u0111\u01a1n v\u1ecb m\u00e9t (m) ho\u1eb7c centimet (cm).<\/li>\n
  • A l\u00e0 bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng (li \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i), lu\u00f4n d\u01b0\u01a1ng.<\/li>\n
  • \u03c9 l\u00e0 t\u1ea7n s\u1ed1 g\u00f3c (rad\/s).<\/li>\n
  • (\u03c9t + \u03c6) l\u00e0 pha dao \u0111\u1ed9ng t\u1ea1i th\u1eddi \u0111i\u1ec3m t, cho bi\u1ebft tr\u1ea1ng th\u00e1i dao \u0111\u1ed9ng.<\/li>\n
  • \u03c6 l\u00e0 pha ban \u0111\u1ea7u (t\u1ea1i t = 0), ph\u1ee5 thu\u1ed9c v\u00e0o c\u00e1ch ch\u1ecdn g\u1ed1c th\u1eddi gian.<\/li>\n<\/ul>\n

    \"dao-dong-dieu-hoa-la-gi-1\"<\/p>\n

    C\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/b><\/h2>\n

    Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a \u0111\u01b0\u1ee3c m\u00f4 t\u1ea3 th\u00f4ng qua m\u1ed9t h\u1ec7 th\u1ed1ng c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng, gi\u00fap bi\u1ec3u di\u1ec5n \u0111\u1ea7y \u0111\u1ee7 \u0111\u1eb7c \u0111i\u1ec3m c\u1ee7a qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng. Vi\u1ec7c n\u1eafm v\u1eefng c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0y l\u00e0 c\u01a1 s\u1edf \u0111\u1ec3 ph\u00e2n t\u00edch, m\u00f4 t\u1ea3 v\u00e0 gi\u1ea3i b\u00e0i t\u1eadp v\u1ec1 s\u1ef1 thay \u0111\u1ed5i tr\u1ea1ng th\u00e1i c\u1ee7a v\u1eadt.<\/p>\n\n\n\n\n\n\n\n\n
    \u0110\u1ea1i l\u01b0\u1ee3ng<\/b><\/th>\nC\u00f4ng th\u1ee9c<\/b><\/th>\n\u0110\u01a1n v\u1ecb<\/b><\/th>\n<\/tr>\n<\/thead>\n
    Chu k\u1ef3 T<\/td>\nT = 2\u03c0\/\u03c9<\/td>\ngi\u00e2y (s)<\/td>\n<\/tr>\n
    T\u1ea7n s\u1ed1 f<\/td>\nf = 1\/T = \u03c9\/2\u03c0<\/td>\nh\u00e9c (Hz)<\/td>\n<\/tr>\n
    T\u1ea7n s\u1ed1 g\u00f3c \u03c9<\/td>\n\u03c9 = 2\u03c0\/T = 2\u03c0f<\/td>\nrad\/s<\/td>\n<\/tr>\n
    Bi\u00ean \u0111\u1ed9 A<\/td>\nA = x c\u1ef1c \u0111\u1ea1i<\/td>\nm ho\u1eb7c cm<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

    Chu k\u1ef3 T l\u00e0 kho\u1ea3ng th\u1eddi gian v\u1eadt th\u1ef1c hi\u1ec7n m\u1ed9t dao \u0111\u1ed9ng to\u00e0n ph\u1ea7n, c\u00f2n t\u1ea7n s\u1ed1 f l\u00e0 s\u1ed1 dao \u0111\u1ed9ng to\u00e0n ph\u1ea7n th\u1ef1c hi\u1ec7n trong m\u1ed9t gi\u00e2y. Ba \u0111\u1ea1i l\u01b0\u1ee3ng T, f, \u03c9 li\u00ean h\u1ec7 ch\u1eb7t ch\u1ebd v\u1edbi nhau n\u00ean khi bi\u1ebft m\u1ed9t \u0111\u1ea1i l\u01b0\u1ee3ng, b\u1ea1n c\u00f3 th\u1ec3 suy ra hai \u0111\u1ea1i l\u01b0\u1ee3ng c\u00f2n l\u1ea1i.<\/p>\n

    V\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/b><\/h2>\n

    V\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c l\u00e0 \u0111\u1ea1o h\u00e0m b\u1eadc nh\u1ea5t v\u00e0 b\u1eadc hai c\u1ee7a li \u0111\u1ed9 theo th\u1eddi gian, n\u00ean c\u0169ng bi\u1ebfn thi\u00ean \u0111i\u1ec1u h\u00f2a c\u00f9ng t\u1ea7n s\u1ed1 g\u00f3c \u03c9 v\u1edbi li \u0111\u1ed9.<\/p>\n

      \n
    • V\u1eadn t\u1ed1c: v = \u2212A\u03c9\u00b7sin(\u03c9t + \u03c6); v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i v\u2098\u2090\u2093 = A\u03c9 \u0111\u1ea1t t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, b\u1eb1ng 0 t\u1ea1i v\u1ecb tr\u00ed bi\u00ean.<\/li>\n
    • Gia t\u1ed1c: a = \u2212\u03c9\u00b2\u00b7x; gia t\u1ed1c c\u1ef1c \u0111\u1ea1i a\u2098\u2090\u2093 = A\u03c9\u00b2 \u0111\u1ea1t t\u1ea1i v\u1ecb tr\u00ed bi\u00ean. Gia t\u1ed1c lu\u00f4n h\u01b0\u1edbng v\u1ec1 v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/li>\n
    • H\u1ec7 th\u1ee9c \u0111\u1ed9c l\u1eadp v\u1edbi th\u1eddi gian: A\u00b2 = x\u00b2 + v\u00b2\/\u03c9\u00b2, gi\u00fap t\u00ednh bi\u00ean \u0111\u1ed9 khi bi\u1ebft li \u0111\u1ed9 v\u00e0 v\u1eadn t\u1ed1c t\u1ea1i m\u1ed9t th\u1eddi \u0111i\u1ec3m.<\/li>\n<\/ul>\n

      \"dao-dong-dieu-hoa-la-gi-2\"<\/p>\n

      N\u0103ng l\u01b0\u1ee3ng trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/b><\/h2>\n

      Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, c\u01a1 n\u0103ng \u0111\u01b0\u1ee3c b\u1ea3o to\u00e0n (khi b\u1ecf qua ma s\u00e1t) v\u00e0 c\u00f3 s\u1ef1 chuy\u1ec3n h\u00f3a li\u00ean t\u1ee5c gi\u1eefa \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng. C\u01a1 n\u0103ng to\u00e0n ph\u1ea7n \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng: W = \u00bd\u00b7k\u00b7A\u00b2 = \u00bd\u00b7m\u00b7\u03c9\u00b2\u00b7A\u00b2.<\/p>\n

        \n
      • \u0110\u1ed9ng n\u0103ng: W\u0111 = \u00bd\u00b7m\u00b7v\u00b2, c\u1ef1c \u0111\u1ea1i t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/li>\n
      • Th\u1ebf n\u0103ng: Wt = \u00bd\u00b7k\u00b7x\u00b2, c\u1ef1c \u0111\u1ea1i t\u1ea1i v\u1ecb tr\u00ed bi\u00ean.<\/li>\n
      • T\u1ed5ng \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng lu\u00f4n kh\u00f4ng \u0111\u1ed5i v\u00e0 b\u1eb1ng c\u01a1 n\u0103ng W.<\/li>\n<\/ul>\n

        \u0110i\u1ec3m quan tr\u1ecdng c\u1ea7n nh\u1edb: \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng bi\u1ebfn thi\u00ean v\u1edbi chu k\u1ef3 b\u1eb1ng m\u1ed9t n\u1eeda chu k\u1ef3 dao \u0111\u1ed9ng (T\/2), c\u00f2n c\u01a1 n\u0103ng th\u00ec kh\u00f4ng \u0111\u1ed5i theo th\u1eddi gian.<\/p>\n

        Con l\u1eafc l\u00f2 xo v\u00e0 con l\u1eafc \u0111\u01a1n<\/b><\/h2>\n

        Hai h\u1ec7 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a quen thu\u1ed9c nh\u1ea5t trong ch\u01b0\u01a1ng tr\u00ecnh l\u00e0 con l\u1eafc l\u00f2 xo v\u00e0 con l\u1eafc \u0111\u01a1n (v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c nh\u1ecf). B\u1ea3ng d\u01b0\u1edbi \u0111\u00e2y t\u00f3m t\u1eaft c\u00f4ng th\u1ee9c t\u1ea7n s\u1ed1 g\u00f3c v\u00e0 chu k\u1ef3 c\u1ee7a hai h\u1ec7 n\u00e0y.<\/p>\n\n\n\n\n\n\n
        H\u1ec7 dao \u0111\u1ed9ng<\/b><\/th>\nT\u1ea7n s\u1ed1 g\u00f3c \u03c9<\/b><\/th>\nChu k\u1ef3 T<\/b><\/th>\n<\/tr>\n<\/thead>\n
        Con l\u1eafc l\u00f2 xo<\/td>\n\u03c9 = \u221a(k\/m)<\/td>\nT = 2\u03c0\u00b7\u221a(m\/k)<\/td>\n<\/tr>\n
        Con l\u1eafc \u0111\u01a1n<\/td>\n\u03c9 = \u221a(g\/l)<\/td>\nT = 2\u03c0\u00b7\u221a(l\/g)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

        V\u1edbi con l\u1eafc l\u00f2 xo, k l\u00e0 \u0111\u1ed9 c\u1ee9ng l\u00f2 xo (N\/m) v\u00e0 m l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt (kg). V\u1edbi con l\u1eafc \u0111\u01a1n, l l\u00e0 chi\u1ec1u d\u00e0i d\u00e2y (m) v\u00e0 g l\u00e0 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng (\u2248 9,8 m\/s\u00b2). Chu k\u1ef3 con l\u1eafc \u0111\u01a1n kh\u00f4ng ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt, ch\u1ec9 ph\u1ee5 thu\u1ed9c chi\u1ec1u d\u00e0i d\u00e2y v\u00e0 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng.<\/p>\n

        V\u00ed d\u1ee5 v\u00e0 b\u00e0i t\u1eadp v\u1eadn d\u1ee5ng c\u00f3 l\u1eddi gi\u1ea3i<\/b><\/h2>\n

        B\u00e0i 1:<\/b> M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi \u03c9 = 2\u03c0 rad\/s. T\u00ednh chu k\u1ef3 v\u00e0 t\u1ea7n s\u1ed1.<\/p>\n

        L\u1eddi gi\u1ea3i: B\u01b0\u1edbc 1, \u00e1p d\u1ee5ng T = 2\u03c0\/\u03c9 = 2\u03c0\/2\u03c0 = 1 s. B\u01b0\u1edbc 2, t\u00ednh t\u1ea7n s\u1ed1 f = 1\/T = 1\/1 = 1 Hz. V\u1eady chu k\u1ef3 l\u00e0 1 s v\u00e0 t\u1ea7n s\u1ed1 l\u00e0 1 Hz.<\/p>\n

        B\u00e0i 2:<\/b> V\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 A = 5 cm, t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 10 rad\/s. T\u00ednh v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i v\u00e0 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i.<\/p>\n

        L\u1eddi gi\u1ea3i: B\u01b0\u1edbc 1, v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i v\u2098\u2090\u2093 = A\u00b7\u03c9 = 5 \u00d7 10 = 50 cm\/s. B\u01b0\u1edbc 2, gia t\u1ed1c c\u1ef1c \u0111\u1ea1i a\u2098\u2090\u2093 = A\u00b7\u03c9\u00b2 = 5 \u00d7 10\u00b2 = 500 cm\/s\u00b2. V\u1eady v\u2098\u2090\u2093 = 50 cm\/s v\u00e0 a\u2098\u2090\u2093 = 500 cm\/s\u00b2.<\/p>\n

        B\u00e0i 3:<\/b> Cho ph\u01b0\u01a1ng tr\u00ecnh x = 4\u00b7cos(5t) (cm; s). X\u00e1c \u0111\u1ecbnh bi\u00ean \u0111\u1ed9, pha ban \u0111\u1ea7u v\u00e0 chu k\u1ef3.<\/p>\n

        L\u1eddi gi\u1ea3i: B\u01b0\u1edbc 1, so s\u00e1nh v\u1edbi d\u1ea1ng x = A\u00b7cos(\u03c9t + \u03c6) ta \u0111\u01b0\u1ee3c A = 4 cm, \u03c9 = 5 rad\/s, \u03c6 = 0. B\u01b0\u1edbc 2, t\u00ednh chu k\u1ef3 T = 2\u03c0\/\u03c9 = 2\u03c0\/5 \u2248 1,26 s. V\u1eady bi\u00ean \u0111\u1ed9 4 cm, pha ban \u0111\u1ea7u 0 v\u00e0 chu k\u1ef3 \u2248 1,26 s.<\/p>\n

        B\u00e0i 4:<\/b> Con l\u1eafc l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 100 N\/m, v\u1eadt n\u1eb7ng m = 1 kg. T\u00ednh t\u1ea7n s\u1ed1 g\u00f3c v\u00e0 chu k\u1ef3 dao \u0111\u1ed9ng.<\/p>\n

        L\u1eddi gi\u1ea3i: B\u01b0\u1edbc 1, t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = \u221a(k\/m) = \u221a(100\/1) = 10 rad\/s. B\u01b0\u1edbc 2, chu k\u1ef3 T = 2\u03c0\/\u03c9 = 2\u03c0\/10 \u2248 0,63 s. V\u1eady \u03c9 = 10 rad\/s v\u00e0 T \u2248 0,63 s.<\/p>\n

        B\u00e0i 5:<\/b> M\u1ed9t v\u1eadt kh\u1ed1i l\u01b0\u1ee3ng m = 200 g dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 A = 10 cm v\u00e0 t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 20 rad\/s. T\u00ednh c\u01a1 n\u0103ng c\u1ee7a v\u1eadt.<\/p>\n

        L\u1eddi gi\u1ea3i: B\u01b0\u1edbc 1, \u0111\u1ed5i \u0111\u01a1n v\u1ecb m = 0,2 kg v\u00e0 A = 0,1 m. B\u01b0\u1edbc 2, \u00e1p d\u1ee5ng W = \u00bd\u00b7m\u00b7\u03c9\u00b2\u00b7A\u00b2 = \u00bd \u00d7 0,2 \u00d7 20\u00b2 \u00d7 0,1\u00b2 = \u00bd \u00d7 0,2 \u00d7 400 \u00d7 0,01 = 0,4 J. V\u1eady c\u01a1 n\u0103ng c\u1ee7a v\u1eadt l\u00e0 0,4 J.<\/p>\n

        B\u00e0i 6 (tr\u1eafc nghi\u1ec7m):<\/b> Gia t\u1ed1c trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a lu\u00f4n h\u01b0\u1edbng v\u1ec1 \u0111\u00e2u? A. V\u1ecb tr\u00ed bi\u00ean. B. V\u1ecb tr\u00ed c\u00e2n b\u1eb1ng. C. C\u00f9ng chi\u1ec1u v\u1eadn t\u1ed1c. D. Ra xa c\u00e2n b\u1eb1ng. \u0110\u00e1p \u00e1n: B, v\u00ec a = \u2212\u03c9\u00b2\u00b7x lu\u00f4n ng\u01b0\u1ee3c d\u1ea5u v\u1edbi li \u0111\u1ed9 n\u00ean h\u01b0\u1edbng v\u1ec1 v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/p>\n

        \"dao-dong-dieu-hoa-la-gi-3\"<\/p>\n

        \u1ee8ng d\u1ee5ng c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/b><\/h2>\n

        Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a kh\u00f4ng ch\u1ec9 l\u00e0 ki\u1ebfn th\u1ee9c l\u00fd thuy\u1ebft m\u00e0 c\u00f2n l\u00e0 m\u00f4 h\u00ecnh g\u1ed1c \u0111\u1ec3 hi\u1ec3u nhi\u1ec1u hi\u1ec7n t\u01b0\u1ee3ng v\u00e0 thi\u1ebft b\u1ecb trong th\u1ef1c t\u1ebf.<\/p>\n

          \n
        • \u0110\u1ed3ng h\u1ed3 qu\u1ea3 l\u1eafc v\u00e0 \u0111\u1ed3ng h\u1ed3 dao \u0111\u1ed9ng d\u00f9ng chu k\u1ef3 \u1ed5n \u0111\u1ecbnh c\u1ee7a con l\u1eafc \u0111\u1ec3 \u0111o th\u1eddi gian.<\/li>\n
        • M\u00e0ng loa, micro v\u00e0 d\u00e2y \u0111\u00e0n dao \u0111\u1ed9ng g\u1ea7n \u0111i\u1ec1u h\u00f2a \u0111\u1ec3 t\u1ea1o v\u00e0 thu \u00e2m thanh.<\/li>\n
        • H\u1ec7 gi\u1ea3m x\u00f3c tr\u00ean \u00f4 t\u00f4, xe m\u00e1y l\u00e0 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 t\u1eaft d\u1ea7n nh\u1edd ma s\u00e1t.<\/li>\n
        • M\u1ea1ch dao \u0111\u1ed9ng LC trong \u0111i\u1ec7n t\u1eed t\u1ea1o s\u00f3ng \u0111i\u1ec7n t\u1eeb theo quy lu\u1eadt \u0111i\u1ec1u h\u00f2a, \u1ee9ng d\u1ee5ng trong ph\u00e1t v\u00e0 thu s\u00f3ng radio.<\/li>\n<\/ul>\n

          C\u00e2u h\u1ecfi th\u01b0\u1eddng g\u1eb7p v\u1ec1 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/b><\/h2>\n

          Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 g\u00ec?<\/b><\/h3>\n

          Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 dao \u0111\u1ed9ng c\u00f3 li \u0111\u1ed9 bi\u1ebfn thi\u00ean theo h\u00e0m cosin (ho\u1eb7c sin) c\u1ee7a th\u1eddi gian, quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng v\u1edbi bi\u00ean \u0111\u1ed9 kh\u00f4ng \u0111\u1ed5i.<\/p>\n

          Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 g\u00ec?<\/b><\/h3>\n

          Ph\u01b0\u01a1ng tr\u00ecnh li \u0111\u1ed9 c\u00f3 d\u1ea1ng x = A\u00b7cos(\u03c9t + \u03c6), trong \u0111\u00f3 A l\u00e0 bi\u00ean \u0111\u1ed9, \u03c9 l\u00e0 t\u1ea7n s\u1ed1 g\u00f3c v\u00e0 \u03c6 l\u00e0 pha ban \u0111\u1ea7u.<\/p>\n

          Chu k\u1ef3 v\u00e0 t\u1ea7n s\u1ed1 li\u00ean h\u1ec7 v\u1edbi nhau th\u1ebf n\u00e0o?<\/b><\/h3>\n

          Chu k\u1ef3 v\u00e0 t\u1ea7n s\u1ed1 l\u00e0 hai \u0111\u1ea1i l\u01b0\u1ee3ng ngh\u1ecbch \u0111\u1ea3o nhau: T = 2\u03c0\/\u03c9 v\u00e0 f = 1\/T = \u03c9\/2\u03c0.<\/p>\n

          V\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a t\u00ednh th\u1ebf n\u00e0o?<\/b><\/h3>\n

          V\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng v\u2098\u2090\u2093 = A\u00b7\u03c9 v\u00e0 \u0111\u1ea1t \u0111\u01b0\u1ee3c khi v\u1eadt \u0111i qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/p>\n

          Gia t\u1ed1c trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 \u0111\u1eb7c \u0111i\u1ec3m g\u00ec?<\/b><\/h3>\n

          Gia t\u1ed1c \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng a = \u2212\u03c9\u00b2\u00b7x, c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i t\u1ea1i v\u1ecb tr\u00ed bi\u00ean v\u00e0 lu\u00f4n h\u01b0\u1edbng v\u1ec1 v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/p>\n

          C\u01a1 n\u0103ng c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 b\u1ea3o to\u00e0n kh\u00f4ng?<\/b><\/h3>\n

          Khi b\u1ecf qua ma s\u00e1t, c\u01a1 n\u0103ng W = \u00bd\u00b7k\u00b7A\u00b2 \u0111\u01b0\u1ee3c b\u1ea3o to\u00e0n, ch\u1ec9 c\u00f3 s\u1ef1 chuy\u1ec3n h\u00f3a qua l\u1ea1i gi\u1eefa \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng.<\/p>\n