{"id":567270,"date":"2026-07-23T09:38:20","date_gmt":"2026-07-23T02:38:20","guid":{"rendered":"https:\/\/hoanghamobile.com\/tin-tuc\/?p=567270"},"modified":"2026-07-23T09:49:05","modified_gmt":"2026-07-23T02:49:05","slug":"da-thuc-la-gi","status":"publish","type":"post","link":"https:\/\/hoanghamobile.com\/tin-tuc\/da-thuc-la-gi\/","title":{"rendered":"\u0110a th\u1ee9c l\u00e0 g\u00ec? Thu g\u1ecdn, b\u1eadc v\u00e0 c\u1ed9ng tr\u1eeb \u0111a th\u1ee9c"},"content":{"rendered":"

\u0110a th\u1ee9c l\u00e0 m\u1ed9t t\u1ed5ng c\u1ee7a nh\u1eefng \u0111\u01a1n th\u1ee9c<\/a>; m\u1ed7i \u0111\u01a1n th\u1ee9c trong t\u1ed5ng \u0111\u00f3 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 m\u1ed9t h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c. V\u00ed d\u1ee5 x\u00b2 + 3xy \u2212 5y + 2 l\u00e0 m\u1ed9t \u0111a th\u1ee9c g\u1ed3m b\u1ed1n h\u1ea1ng t\u1eed. \u0110a th\u1ee9c l\u00e0 ki\u1ebfn th\u1ee9c c\u1ed1t l\u00f5i c\u1ee7a \u0110\u1ea1i s\u1ed1 l\u1edbp 7, l\u00e0m n\u1ec1n cho vi\u1ec7c r\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c v\u00e0 gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh. C\u00f9ng t\u00ecm hi\u1ec3u <\/span>\u0111a th\u1ee9c l\u00e0 g\u00ec<\/b>, c\u00e1ch thu g\u1ecdn, x\u00e1c \u0111\u1ecbnh b\u1eadc, c\u1ed9ng tr\u1eeb \u0111a th\u1ee9c, \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn v\u00e0 b\u00e0i t\u1eadp v\u1eadn d\u1ee5ng c\u00f3 l\u1eddi gi\u1ea3i chi ti\u1ebft ngay sau \u0111\u00e2y.<\/span><\/p>\n

\u0110a th\u1ee9c l\u00e0 g\u00ec?<\/b><\/h2>\n

\u0110a th\u1ee9c l\u00e0 t\u1ed5ng c\u1ee7a nh\u1eefng \u0111\u01a1n th\u1ee9c, v\u00e0 m\u1ed7i \u0111\u01a1n th\u1ee9c trong t\u1ed5ng g\u1ecdi l\u00e0 m\u1ed9t h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c \u0111\u00f3. M\u1ed9t \u0111\u01a1n th\u1ee9c c\u0169ng \u0111\u01b0\u1ee3c coi l\u00e0 m\u1ed9t \u0111a th\u1ee9c (\u0111a th\u1ee9c ch\u1ec9 c\u00f3 m\u1ed9t h\u1ea1ng t\u1eed). V\u00ed d\u1ee5: 3x\u00b2 + 2x \u2212 1; xy + y\u00b2; hay \u0111\u01a1n gi\u1ea3n l\u00e0 5x \u0111\u1ec1u l\u00e0 \u0111a th\u1ee9c.<\/span><\/p>\n

\"da-thuc-la-gi-1\"<\/p>\n

Ph\u00e2n bi\u1ec7t \u0111\u01a1n th\u1ee9c v\u00e0 \u0111a th\u1ee9c<\/b><\/h2>\n

Nhi\u1ec1u b\u1ea1n hay nh\u1ea7m l\u1eabn gi\u1eefa \u0111\u01a1n th\u1ee9c v\u00e0 \u0111a th\u1ee9c. B\u1ea3ng d\u01b0\u1edbi \u0111\u00e2y t\u00f3m t\u1eaft \u0111i\u1ec3m kh\u00e1c nhau c\u01a1 b\u1ea3n \u0111\u1ec3 b\u1ea1n d\u1ec5 ghi nh\u1edb.<\/span><\/p>\n\n\n\n\n\n\n\n\n
Ti\u00eau ch\u00ed<\/th>\n\u0110\u01a1n th\u1ee9c<\/th>\n\u0110a th\u1ee9c<\/th>\n<\/tr>\n<\/thead>\n
Kh\u00e1i ni\u1ec7m<\/td>\nBi\u1ec3u th\u1ee9c ch\u1ec9 g\u1ed3m t\u00edch c\u1ee7a m\u1ed9t s\u1ed1 v\u1edbi c\u00e1c bi\u1ebfn<\/td>\nT\u1ed5ng c\u1ee7a m\u1ed9t hay nhi\u1ec1u \u0111\u01a1n th\u1ee9c<\/td>\n<\/tr>\n
S\u1ed1 h\u1ea1ng t\u1eed<\/td>\n\u0110\u00fang m\u1ed9t h\u1ea1ng t\u1eed<\/td>\nM\u1ed9t ho\u1eb7c nhi\u1ec1u h\u1ea1ng t\u1eed<\/td>\n<\/tr>\n
V\u00ed d\u1ee5<\/td>\n3x\u00b2, \u22125xy, 7<\/td>\n3x\u00b2 + 2x \u2212 1, xy + y\u00b2<\/td>\n<\/tr>\n
Quan h\u1ec7<\/td>\nL\u00e0 tr\u01b0\u1eddng h\u1ee3p ri\u00eang c\u1ee7a \u0111a th\u1ee9c<\/td>\nBao h\u00e0m c\u1ea3 \u0111\u01a1n th\u1ee9c<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Thu g\u1ecdn \u0111a th\u1ee9c<\/b><\/h2>\n

Thu g\u1ecdn \u0111a th\u1ee9c l\u00e0 qu\u00e1 tr\u00ecnh c\u1ed9ng ho\u1eb7c tr\u1eeb c\u00e1c h\u1ea1ng t\u1eed \u0111\u1ed3ng d\u1ea1ng \u0111\u1ec3 \u0111\u01b0a \u0111a th\u1ee9c v\u1ec1 d\u1ea1ng \u0111\u01a1n gi\u1ea3n nh\u1ea5t, trong \u0111\u00f3 kh\u00f4ng c\u00f2n hai h\u1ea1ng t\u1eed n\u00e0o \u0111\u1ed3ng d\u1ea1ng.<\/span><\/p>\n

V\u00ed d\u1ee5, thu g\u1ecdn \u0111a th\u1ee9c 3x\u00b2 + 2xy \u2212 x\u00b2 + 5xy:<\/span><\/p>\n

    \n
  • B\u01b0\u1edbc 1 \u2013 Nh\u00f3m c\u00e1c h\u1ea1ng t\u1eed \u0111\u1ed3ng d\u1ea1ng: (3x\u00b2 \u2212 x\u00b2) + (2xy + 5xy).<\/span><\/li>\n
  • B\u01b0\u1edbc 2 \u2013 C\u1ed9ng, tr\u1eeb h\u1ec7 s\u1ed1 v\u00e0 gi\u1eef nguy\u00ean ph\u1ea7n bi\u1ebfn: 2x\u00b2 + 7xy.<\/span><\/li>\n<\/ul>\n

    Khi th\u1ef1c hi\u1ec7n thu g\u1ecdn \u0111a th\u1ee9c, b\u1ea1n n\u00ean nh\u00f3m c\u00e1c h\u1ea1ng t\u1eed \u0111\u1ed3ng d\u1ea1ng tr\u01b0\u1edbc, sau \u0111\u00f3 c\u1ed9ng ho\u1eb7c tr\u1eeb c\u00e1c h\u1ec7 s\u1ed1 v\u00e0 gi\u1eef nguy\u00ean ph\u1ea7n bi\u1ebfn. C\u00e1ch l\u00e0m n\u00e0y gi\u00fap h\u1ea1n ch\u1ebf sai s\u00f3t v\u00e0 r\u00fat ng\u1eafn th\u1eddi gian t\u00ednh to\u00e1n.<\/span><\/p>\n

    B\u1eadc c\u1ee7a \u0111a th\u1ee9c l\u00e0 g\u00ec<\/b><\/h2>\n

    B\u1eadc c\u1ee7a m\u1ed9t \u0111a th\u1ee9c l\u00e0 b\u1eadc c\u1ee7a h\u1ea1ng t\u1eed c\u00f3 b\u1eadc cao nh\u1ea5t trong d\u1ea1ng thu g\u1ecdn c\u1ee7a \u0111a th\u1ee9c \u0111\u00f3. V\u00ec v\u1eady, khi x\u00e1c \u0111\u1ecbnh b\u1eadc c\u1ee7a \u0111a th\u1ee9c, tr\u01b0\u1edbc h\u1ebft c\u1ea7n thu g\u1ecdn \u0111a th\u1ee9c v\u00e0 t\u00ecm h\u1ea1ng t\u1eed c\u00f3 b\u1eadc l\u1edbn nh\u1ea5t.<\/span><\/p>\n

    V\u00ed d\u1ee5, \u0111a th\u1ee9c 2x\u00b2y + 3xy \u2212 1 c\u00f3 c\u00e1c h\u1ea1ng t\u1eed l\u1ea7n l\u01b0\u1ee3t l\u00e0 2x\u00b2y, 3xy v\u00e0 \u22121, v\u1edbi b\u1eadc t\u01b0\u01a1ng \u1ee9ng l\u00e0 3, 2 v\u00e0 0. Do \u0111\u00f3, b\u1eadc c\u1ee7a \u0111a th\u1ee9c n\u00e0y l\u00e0 3.<\/span><\/p>\n

    L\u01b0u \u00fd: S\u1ed1 0 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 \u0111a th\u1ee9c kh\u00f4ng v\u00e0 kh\u00f4ng c\u00f3 b\u1eadc x\u00e1c \u0111\u1ecbnh. \u0110\u00e2y l\u00e0 tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t c\u1ea7n ghi nh\u1edb khi l\u00e0m c\u00e1c b\u00e0i to\u00e1n li\u00ean quan \u0111\u1ebfn b\u1eadc c\u1ee7a \u0111a th\u1ee9c.<\/span><\/p>\n

    \"da-thuc-la-gi-2\"<\/p>\n

    C\u1ed9ng, tr\u1eeb \u0111a th\u1ee9c<\/b><\/h2>\n

    \u0110\u1ec3 c\u1ed9ng ho\u1eb7c tr\u1eeb hai \u0111a th\u1ee9c, ta vi\u1ebft c\u00e1c \u0111a th\u1ee9c c\u1ea1nh nhau, \u0111\u1ed3ng th\u1eddi ch\u00fa \u00fd \u0111\u1ebfn d\u1ea5u c\u1ee7a t\u1eebng h\u1ea1ng t\u1eed, \u0111\u1eb7c bi\u1ec7t l\u00e0 khi th\u1ef1c hi\u1ec7n ph\u00e9p tr\u1eeb. Sau \u0111\u00f3, ta nh\u00f3m c\u00e1c h\u1ea1ng t\u1eed \u0111\u1ed3ng d\u1ea1ng v\u00e0 ti\u1ebfn h\u00e0nh thu g\u1ecdn.<\/span><\/p>\n

    V\u00ed d\u1ee5: A = 2x\u00b2 + 3x \u2212 1; B = x\u00b2 \u2212 5x + 4.<\/span><\/p>\n

    Khi \u0111\u00f3: A + B = (2x\u00b2 + x\u00b2) + (3x \u2212 5x) + (\u22121 + 4) = 3x\u00b2 \u2212 2x + 3.<\/span><\/p>\n

    V\u1edbi ph\u00e9p tr\u1eeb, b\u1ea1n c\u1ea7n b\u1ecf ngo\u1eb7c v\u00e0 \u0111\u1ed5i d\u1ea5u t\u1ea5t c\u1ea3 c\u00e1c h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c \u0111\u1ee9ng sau d\u1ea5u tr\u1eeb: A \u2212 B = (2x\u00b2 \u2212 x\u00b2) + (3x + 5x) + (\u22121 \u2212 4) = x\u00b2 + 8x \u2212 5.<\/span><\/p>\n

    \u0110a th\u1ee9c m\u1ed9t bi\u1ebfn v\u00e0 nghi\u1ec7m<\/b><\/h2>\n

    \u0110a th\u1ee9c m\u1ed9t bi\u1ebfn l\u00e0 g\u00ec?<\/b> \u0110\u00e2y l\u00e0 \u0111a th\u1ee9c ch\u1ec9 ch\u1ee9a m\u1ed9t bi\u1ebfn duy nh\u1ea5t, th\u01b0\u1eddng \u0111\u01b0\u1ee3c s\u1eafp x\u1ebfp theo l\u0169y th\u1eeba gi\u1ea3m d\u1ea7n c\u1ee7a bi\u1ebfn \u0111\u1ec3 d\u1ec5 quan s\u00e1t v\u00e0 th\u1ef1c hi\u1ec7n c\u00e1c ph\u00e9p t\u00ednh. V\u00ed d\u1ee5: P(x) = 2x\u00b3 \u2212 x\u00b2 + 4x \u2212 7.<\/span><\/p>\n

    Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ebfn x l\u00e0m cho gi\u00e1 tr\u1ecb c\u1ee7a \u0111a th\u1ee9c b\u1eb1ng 0 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c. \u0110\u1ec3 ki\u1ec3m tra m\u1ed9t gi\u00e1 tr\u1ecb c\u00f3 ph\u1ea3i l\u00e0 nghi\u1ec7m hay kh\u00f4ng, ta thay gi\u00e1 tr\u1ecb \u0111\u00f3 v\u00e0o \u0111a th\u1ee9c r\u1ed3i t\u00ednh k\u1ebft qu\u1ea3.<\/span><\/p>\n

    C\u1ee5 th\u1ec3, v\u1edbi x = x\u2080, ta t\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a \u0111a th\u1ee9c t\u1ea1i x\u2080. N\u1ebfu k\u1ebft qu\u1ea3 thu \u0111\u01b0\u1ee3c b\u1eb1ng 0 th\u00ec x\u2080 l\u00e0 nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c.<\/span><\/p>\n

    \"da-thuc-la-gi-3\"<\/p>\n

    Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi \u0111a th\u1ee9c<\/b><\/h2>\n

    \u0110\u1ec3 nh\u00e2n m\u1ed9t \u0111\u01a1n th\u1ee9c v\u1edbi m\u1ed9t \u0111a th\u1ee9c, ta l\u1ea5y \u0111\u01a1n th\u1ee9c \u0111\u00f3 nh\u00e2n l\u1ea7n l\u01b0\u1ee3t v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c, sau \u0111\u00f3 c\u1ed9ng c\u00e1c k\u1ebft qu\u1ea3 thu \u0111\u01b0\u1ee3c l\u1ea1i v\u1edbi nhau.<\/span><\/p>\n

    V\u00ed d\u1ee5: 2x\u00b7(x\u00b2 + 3x \u2212 1) = 2x\u00b7x\u00b2 + 2x\u00b73x + 2x\u00b7(\u22121) = 2x\u00b3 + 6x\u00b2 \u2212 2x.<\/span><\/p>\n

    \u0110\u00e2y l\u00e0 m\u1ed9t ph\u00e9p bi\u1ebfn \u0111\u1ed5i \u0111\u1ea1i s\u1ed1 c\u01a1 b\u1ea3n, \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng th\u01b0\u1eddng xuy\u00ean trong qu\u00e1 tr\u00ecnh r\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c, \u0111\u1ed3ng th\u1eddi l\u00e0 n\u1ec1n t\u1ea3ng \u0111\u1ec3 gi\u1ea3i c\u00e1c b\u00e0i to\u00e1n v\u1ec1 ph\u01b0\u01a1ng tr\u00ecnh v\u00e0 \u0111\u1ea1i s\u1ed1 \u1edf c\u00e1c l\u1edbp h\u1ecdc cao h\u01a1n.<\/span><\/p>\n

    Nh\u1eefng l\u1ed7i th\u01b0\u1eddng g\u1eb7p khi l\u00e0m b\u00e0i v\u1ec1 \u0111a th\u1ee9c<\/b><\/h2>\n

    Khi l\u00e0m b\u00e0i t\u1eadp v\u1ec1 \u0111a th\u1ee9c, b\u1ea1n n\u00ean tr\u00e1nh m\u1ed9t v\u00e0i l\u1ed7i ph\u1ed5 bi\u1ebfn sau \u0111\u1ec3 kh\u00f4ng b\u1ecb m\u1ea5t \u0111i\u1ec3m \u0111\u00e1ng ti\u1ebfc:<\/span><\/p>\n

      \n
    • C\u1ed9ng nh\u1ea7m c\u00e1c h\u1ea1ng t\u1eed kh\u00f4ng \u0111\u1ed3ng d\u1ea1ng, v\u00ed d\u1ee5 g\u1ed9p 3x\u00b2 v\u1edbi 2x th\u00e0nh 5x\u00b3 \u2013 \u0111\u00e2y l\u00e0 sai l\u1ea7m hay g\u1eb7p nh\u1ea5t.<\/span><\/li>\n
    • Qu\u00ean \u0111\u1ed5i d\u1ea5u khi b\u1ecf ngo\u1eb7c trong ph\u00e9p tr\u1eeb hai \u0111a th\u1ee9c.<\/span><\/li>\n
    • X\u00e1c \u0111\u1ecbnh b\u1eadc khi ch\u01b0a thu g\u1ecdn, d\u1eabn \u0111\u1ebfn k\u1ebft lu\u1eadn sai v\u1ec1 b\u1eadc c\u1ee7a \u0111a th\u1ee9c.<\/span><\/li>\n
    • T\u00ednh sai b\u1eadc c\u1ee7a h\u1ea1ng t\u1eed nhi\u1ec1u bi\u1ebfn: b\u1eadc b\u1eb1ng t\u1ed5ng s\u1ed1 m\u0169 c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c bi\u1ebfn, v\u00ed d\u1ee5 x\u00b2y c\u00f3 b\u1eadc 3 ch\u1ee9 kh\u00f4ng ph\u1ea3i 2.<\/span><\/li>\n<\/ul>\n

      B\u00e0i t\u1eadp v\u1eadn d\u1ee5ng c\u00f3 l\u1eddi gi\u1ea3i<\/b><\/h2>\n

      B\u00e0i 1: Thu g\u1ecdn \u0111a th\u1ee9c 4x\u00b2 + 3x \u2212 2x\u00b2 + x. L\u1eddi gi\u1ea3i: = (4x\u00b2 \u2212 2x\u00b2) + (3x + x) = 2x\u00b2 + 4x.<\/span><\/p>\n

      B\u00e0i 2: T\u00ecm b\u1eadc c\u1ee7a \u0111a th\u1ee9c 5x\u00b3y \u2212 2xy + 7. L\u1eddi gi\u1ea3i: h\u1ea1ng t\u1eed 5x\u00b3y c\u00f3 b\u1eadc 4 (cao nh\u1ea5t), n\u00ean b\u1eadc \u0111a th\u1ee9c l\u00e0 4.<\/span><\/p>\n

      B\u00e0i 3: T\u00ednh A + B v\u1edbi A = x\u00b2 + 2x, B = 3x\u00b2 \u2212 x + 1. L\u1eddi gi\u1ea3i: = (x\u00b2 + 3x\u00b2) + (2x \u2212 x) + 1 = 4x\u00b2 + x + 1.<\/span><\/p>\n

      B\u00e0i 4: T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a P(x) = 2x\u00b2 \u2212 3x + 1 t\u1ea1i x = 2. L\u1eddi gi\u1ea3i: P(2) = 2\u00b74 \u2212 3\u00b72 + 1 = 8 \u2212 6 + 1 = 3.<\/span><\/p>\n

      B\u00e0i 5 (tr\u1eafc nghi\u1ec7m): \u0110a th\u1ee9c 3x\u00b2 + 2x \u2212 5 c\u00f3 b\u1eadc b\u1eb1ng bao nhi\u00eau? A. 1 B. 2 C. 3 D. 5. \u0110\u00e1p \u00e1n: B.<\/span><\/p>\n

      \"da-thuc-la-gi-4\"<\/p>\n

      C\u00e2u h\u1ecfi th\u01b0\u1eddng g\u1eb7p v\u1ec1 \u0111a th\u1ee9c<\/b><\/h2>\n

      \u0110a th\u1ee9c l\u00e0 g\u00ec?<\/b><\/h3>\n

      \u0110a th\u1ee9c l\u00e0 t\u1ed5ng c\u1ee7a nh\u1eefng \u0111\u01a1n th\u1ee9c; m\u1ed7i \u0111\u01a1n th\u1ee9c trong t\u1ed5ng l\u00e0 m\u1ed9t h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c.<\/span><\/p>\n

      B\u1eadc c\u1ee7a \u0111a th\u1ee9c \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh th\u1ebf n\u00e0o?<\/b><\/h3>\n

      B\u1eadc c\u1ee7a \u0111a th\u1ee9c l\u00e0 b\u1eadc cao nh\u1ea5t trong c\u00e1c h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c sau khi \u0111\u00e3 thu g\u1ecdn.<\/span><\/p>\n

      Thu g\u1ecdn \u0111a th\u1ee9c l\u00e0 l\u00e0m g\u00ec?<\/b><\/h3>\n

      Thu g\u1ecdn \u0111a th\u1ee9c l\u00e0 c\u1ed9ng, tr\u1eeb c\u00e1c h\u1ea1ng t\u1eed \u0111\u1ed3ng d\u1ea1ng \u0111\u1ec3 \u0111a th\u1ee9c kh\u00f4ng c\u00f2n h\u1ea1ng t\u1eed \u0111\u1ed3ng d\u1ea1ng n\u00e0o.<\/span><\/p>\n

      Nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn l\u00e0 g\u00ec?<\/b><\/h3>\n

      Nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn l\u00e0 gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ebfn l\u00e0m cho \u0111a th\u1ee9c nh\u1eadn gi\u00e1 tr\u1ecb b\u1eb1ng 0.<\/span><\/p>\n

      \u0110\u01a1n th\u1ee9c c\u00f3 ph\u1ea3i \u0111a th\u1ee9c kh\u00f4ng?<\/b><\/h3>\n

      C\u00f3, m\u1ed9t \u0111\u01a1n th\u1ee9c c\u0169ng l\u00e0 m\u1ed9t \u0111a th\u1ee9c (\u0111a th\u1ee9c c\u00f3 m\u1ed9t h\u1ea1ng t\u1eed duy nh\u1ea5t).<\/span><\/p>\n

      \u0110a th\u1ee9c kh\u00f4ng l\u00e0 g\u00ec?<\/b><\/h3>\n

      \u0110a th\u1ee9c kh\u00f4ng l\u00e0 s\u1ed1 0. \u0110\u00e2y l\u00e0 \u0111a th\u1ee9c \u0111\u1eb7c bi\u1ec7t v\u00e0 kh\u00f4ng c\u00f3 b\u1eadc x\u00e1c \u0111\u1ecbnh.<\/span><\/p>\n

      K\u1ebft lu\u1eadn<\/b><\/h2>\n

      T\u00f3m l\u1ea1i, \u0111a th\u1ee9c l\u00e0 t\u1ed5ng c\u1ee7a nh\u1eefng \u0111\u01a1n th\u1ee9c, c\u00f3 b\u1eadc b\u1eb1ng b\u1eadc cao nh\u1ea5t c\u1ee7a c\u00e1c h\u1ea1ng t\u1eed sau khi thu g\u1ecdn. N\u1eafm v\u1eefng c\u00e1ch thu g\u1ecdn, c\u1ed9ng tr\u1eeb v\u00e0 t\u00ecm b\u1eadc \u0111a th\u1ee9c s\u1ebd gi\u00fap b\u1ea1n gi\u1ea3i t\u1ed1t c\u00e1c b\u00e0i to\u00e1n \u0111\u1ea1i s\u1ed1. \u0110\u1ec3 h\u1ecdc th\u00eam, m\u1eddi b\u1ea1n tham kh\u1ea3o c\u00e1c b\u00e0i<\/span> t\u1eadp h\u1ee3p s\u1ed1 nguy\u00ean Z l\u00e0 g\u00ec<\/span><\/a>,<\/span> c\u00f4ng th\u1ee9c t\u1ed5 h\u1ee3p, ch\u1ec9nh h\u1ee3p<\/span><\/a> v\u00e0<\/span> m\u1ed9t n\u0103m \u00e1nh s\u00e1ng b\u1eb1ng bao nhi\u00eau km<\/span><\/a> tr\u00ean chuy\u00ean m\u1ee5c tin t\u1ee9c c\u1ee7a Ho\u00e0ng H\u00e0 Mobile.<\/span><\/p>\n

      Xem th\u00eam:<\/b><\/p>\n

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      • \n

        Elip l\u00e0 g\u00ec? Ph\u01b0\u01a1ng tr\u00ecnh ch\u00ednh t\u1eafc v\u00e0 c\u00e1c y\u1ebfu t\u1ed1<\/a><\/p>\n<\/li>\n

      • \n

        \u0110\u01b0\u1eddng tr\u00f2n l\u00e0 g\u00ec? Y\u1ebfu t\u1ed1, chu vi, di\u1ec7n t\u00edch v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh<\/a><\/p>\n<\/li>\n<\/ul>\n